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<h1>
<img border="0" src="boost.png" align="center" width="277" height="86">enable_if</h1>
<BR>
<BR>
Copyright 2003 Jaakko J&auml;rvi, Jeremiah Willcock, Andrew Lumsdaine.<BR>
<BR>
<!--TOC section Introduction-->

<H2><A NAME="htoc1">1</A>&nbsp;&nbsp;Introduction</H2><!--SEC END -->

<A NAME="introduction"></A>
The <TT>enable_if</TT> family of templates is a set of tools to allow a function template or a class template specialization 
to include or exclude itself from a set of matching functions or specializations
based on properties of its template arguments. 
For example, one can define function templates that
are only enabled for, and thus only match, an arbitrary set of types
defined by a traits class. The <TT>enable_if</TT> templates can also be
applied to enable class template specializations. Applications of
<TT>enable_if</TT> are discussed in length
in&nbsp;[<A HREF="#jarvi:03:cuj_arbitrary_overloading"><CITE>1</CITE></A>] and&nbsp;[<A HREF="#jarvi:03:c++typeclasses"><CITE>2</CITE></A>].<BR>
<BR>
<!--TOC subsection Synopsis-->

<H3><A NAME="htoc2">1.1</A>&nbsp;&nbsp;Synopsis</H3><!--SEC END -->

<A NAME="sec:synopsis"></A>
<PRE>namespace boost {
  template &lt;class Cond, class T = void&gt; struct enable_if;
  template &lt;class Cond, class T = void&gt; struct disable_if;
  template &lt;class Cond, class T&gt; struct lazy_enable_if;
  template &lt;class Cond, class T&gt; struct lazy_disable_if;

  template &lt;bool B, class T = void&gt; struct enable_if_c;
  template &lt;bool B, class T = void&gt; struct disable_if_c;
  template &lt;bool B, class T&gt; struct lazy_enable_if_c;
  template &lt;bool B, class T&gt; struct lazy_disable_if_c;
}
</PRE>
<!--TOC subsection Background-->

<H3><A NAME="htoc3">1.2</A>&nbsp;&nbsp;Background</H3><!--SEC END -->

<A NAME="sec:background"></A>
Sensible operation of template function overloading in C++ relies
on the <EM>SFINAE</EM> (substitution-failure-is-not-an-error)
principle&nbsp;[<A HREF="#vandevoorde2002:templates"><CITE>3</CITE></A>]: if an invalid argument
or return type is formed during the instantiation of a function
template, the instantiation is removed from the overload resolution
set instead of causing a compilation error. The following example, 
taken from&nbsp;[<A HREF="#jarvi:03:cuj_arbitrary_overloading"><CITE>1</CITE></A>],
demonstrates why this is important:
<PRE>int negate(int i) { return -i; }

template &lt;class F&gt;
typename F::result_type negate(const F&amp; f) { return -f(); }

</PRE>
Suppose the compiler encounters the call <TT>negate(1)</TT>. The first
definition is obviously a better match, but the compiler must
nevertheless consider (and instantiate the prototypes) of both
definitions to find this out. Instantiating the latter definition with
<TT>F</TT> as <TT>int</TT> would result in:
<PRE>int::result_type negate(const int&amp;);

</PRE>
where the return type is invalid. If this was an error, adding an unrelated function template 
(that was never called) could break otherwise valid code.
Due to the SFINAE principle the above example is not, however, erroneous. 
The latter definition of <TT>negate</TT> is simply removed from the overload resolution set.<BR>
<BR>
The <TT>enable_if</TT> templates are tools for controlled creation of the SFINAE
conditions.<BR>
<BR>
<!--TOC section The <TT>enable_if</TT> templates-->

<H2><A NAME="htoc4">2</A>&nbsp;&nbsp;The <TT>enable_if</TT> templates</H2><!--SEC END -->

<A NAME="enable_if"></A>
The names of the <TT>enable_if</TT> templates have three parts: an optional <TT>lazy_</TT> tag, 
either <TT>enable_if</TT> or <TT>disable_if</TT>, and an optional <TT>_c</TT> tag.
All eight combinations of these parts are supported.
The meaning of the <TT>lazy_</TT> tag is described in Section&nbsp;<A HREF="#sec:enable_if_lazy">3.3</A>.
The second part of the name indicates whether a true condition argument should 
enable or disable the current overload.
The third part of the name indicates whether the condition argument is a <TT>bool</TT> value 
(<TT>_c</TT> suffix), or a type containing a static <TT>bool</TT> constant named <TT>value</TT> (no suffix).
The latter version interoperates with Boost.MPL. <BR>
<BR>
The definitions of <TT>enable_if_c</TT> and <TT>enable_if</TT> are as follows (we use <TT>enable_if</TT> templates 
unqualified but they are in the <TT>boost</TT> namespace).
<PRE>template &lt;bool B, class T = void&gt;
struct enable_if_c {
  typedef T type;
};

template &lt;class T&gt;
struct enable_if_c&lt;false, T&gt; {};

template &lt;class Cond, class T = void&gt;
struct enable_if : public enable_if_c&lt;Cond::value, T&gt; {};

</PRE>
An instantiation of the <TT>enable_if_c</TT> template with the parameter
<TT>B</TT> as <TT>true</TT> contains a member type <TT>type</TT>, defined
to be <TT>T</TT>. If <TT>B</TT> is
<TT>false</TT>, no such member is defined. Thus 
<TT>enable_if_c&lt;B, T&gt;::type</TT> is either a valid or an invalid type
expression, depending on the value of <TT>B</TT>.
When valid, <TT>enable_if_c&lt;B, T&gt;::type</TT> equals <TT>T</TT>.
The <TT>enable_if_c</TT> template can thus be used for controlling when functions are considered for
overload resolution and when they are not. 
For example, the following function is defined for all arithmetic types (according to the
classification of the <A HREF="http://www.boost.org/doc/libs/release/libs/type_traits/index.html">Boost type_traits library</A>):
<PRE>template &lt;class T&gt;
typename enable_if_c&lt;boost::is_arithmetic&lt;T&gt;::value, T&gt;::type 
foo(T t) { return t; }

</PRE>
The <TT>disable_if_c</TT> template is provided as well, and has the
same functionality as <TT>enable_if_c</TT> except for the negated condition. The following
function is enabled for all non-arithmetic types.
<PRE>template &lt;class T&gt;
typename disable_if_c&lt;boost::is_arithmetic&lt;T&gt;::value, T&gt;::type 
bar(T t) { return t; }

</PRE>
For easier syntax in some cases and interoperation with Boost.MPL we provide versions of
the <TT>enable_if</TT> templates taking any type with a <TT>bool</TT> member constant named 
<TT>value</TT> as the condition argument.
The MPL <TT>bool_</TT>, <TT>and_</TT>, <TT>or_</TT>, and <TT>not_</TT> templates are likely to be 
useful for creating such types. Also, the traits classes in the Boost.Type_traits library 
follow this convention. 
For example, the above example function <TT>foo</TT> can be alternatively written as:
<PRE>template &lt;class T&gt;
typename enable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
foo(T t) { return t; }

</PRE>
<!--TOC section Using <TT>enable_if</TT>-->

<H2><A NAME="htoc5">3</A>&nbsp;&nbsp;Using <TT>enable_if</TT></H2><!--SEC END -->

<A NAME="sec:using_enable_if"></A>
The <TT>enable_if</TT> templates are defined in
<TT>boost/utility/enable_if.hpp</TT>, which is included by <TT>boost/utility.hpp</TT>.<BR>
<BR>
The <TT>enable_if</TT> template can be used either as the return type, or as an 
extra argument. For example, the <TT>foo</TT> function in the previous section could also be written
as:
<PRE>template &lt;class T&gt;
T foo(T t, typename enable_if&lt;boost::is_arithmetic&lt;T&gt; &gt;::type* dummy = 0); 

</PRE>Hence, an extra parameter of type <TT>void*</TT> is added, but it is given 
a default value to keep the parameter hidden from client code.
Note that the second template argument was not given to <TT>enable_if</TT>, as the default 
<TT>void</TT> gives the desired behavior.<BR>
<BR>
Whether to write the enabler as an argument or within the return type is
largely a matter of taste, but for certain functions, only one
alternative is possible:
<UL><LI>
Operators have a fixed number of arguments, thus <TT>enable_if</TT> must be used in the return type.
<LI>Constructors and destructors do not have a return type; an extra argument is the only option.
<LI>There does not seem to be a way to specify an enabler for a conversion operator. Converting constructors,
however, can have enablers as extra default arguments.
</UL>
<!--TOC subsection Enabling template class specializations-->

<H3><A NAME="htoc6">3.1</A>&nbsp;&nbsp;Enabling template class specializations</H3><!--SEC END -->

<A NAME="sec:enable_if_classes"></A>
Class template specializations can be enabled or disabled with <TT>enable_if</TT>.
One extra template parameter needs to be added for the enabler expressions.
This parameter has the default value <TT>void</TT>.
For example:
<PRE>template &lt;class T, class Enable = void&gt; 
class A { ... };

template &lt;class T&gt;
class A&lt;T, typename enable_if&lt;is_integral&lt;T&gt; &gt;::type&gt; { ... };

template &lt;class T&gt;
class A&lt;T, typename enable_if&lt;is_float&lt;T&gt; &gt;::type&gt; { ... };

</PRE>Instantiating <TT>A</TT> with any integral type matches the first specialization,
whereas any floating point type matches the second one. All other types
match the primary template.
The condition can be any compile-time boolean expression that depends on the 
template arguments of the class.
Note that again, the second argument to <TT>enable_if</TT> is not needed; the default (<TT>void</TT>) 
is the correct value.<BR>
<BR>
<!--TOC subsection Overlapping enabler conditions-->

<H3><A NAME="htoc7">3.2</A>&nbsp;&nbsp;Overlapping enabler conditions</H3><!--SEC END -->

<A NAME="sec:overlapping_conditions"></A>
Once the compiler has examined the enabling conditions and included the
function into the overload resolution set, normal C++ overload resolution 
rules are used to select the best matching function.
In particular, there is no ordering between enabling conditions.
Function templates with enabling conditions that are not mutually exclusive can 
lead to ambiguities. For example:
<PRE>template &lt;class T&gt;
typename enable_if&lt;boost::is_integral&lt;T&gt;, void&gt;::type 
foo(T t) {}

template &lt;class T&gt;
typename enable_if&lt;boost::is_arithmetic&lt;T&gt;, void&gt;::type 
foo(T t) {}

</PRE>
All integral types are also arithmetic. Therefore, say, for the call <TT>foo(1)</TT>,
both conditions are true and both functions are thus in the overload resolution set.
They are both equally good matches and thus ambiguous.
Of course, more than one enabling condition can be simultaneously true as long as 
other arguments disambiguate the functions.<BR>
<BR>
The above discussion applies to using <TT>enable_if</TT> in class template
partial specializations as well.<BR>
<BR>
<!--TOC subsection Lazy <TT>enable_if</TT>-->

<H3><A NAME="htoc8">3.3</A>&nbsp;&nbsp;Lazy <TT>enable_if</TT></H3><!--SEC END -->

<A NAME="sec:enable_if_lazy"></A>
In some cases it is necessary to avoid instantiating part of a
function signature unless an enabling condition is true. For example:
<PRE>template &lt;class T, class U&gt; class mult_traits;

template &lt;class T, class U&gt;
typename enable_if&lt;is_multipliable&lt;T, U&gt;, typename mult_traits&lt;T, U&gt;::type&gt;::type
operator*(const T&amp; t, const U&amp; u) { ... }

</PRE>Assume the class template <TT>mult_traits</TT> is a traits class defining 
the resulting type of a multiplication operator. The <TT>is_multipliable</TT> traits
class specifies for which types to enable the operator. Whenever
<TT>is_multipliable&lt;A, B&gt;::value</TT> is <TT>true</TT> for some types <TT>A</TT> and <TT>B</TT>,
then <TT>mult_traits&lt;A, B&gt;::type</TT> is defined.<BR>
<BR>
Now, trying to invoke (some other overload) of <TT>operator*</TT> with, say, operand types <TT>C</TT> and <TT>D</TT> 
for which <TT>is_multipliable&lt;C, D&gt;::value</TT> is <TT>false</TT> 
and <TT>mult_traits&lt;C, D&gt;::type</TT> is not defined is an error on some compilers. 
The SFINAE principle is not applied because
the invalid type occurs as an argument to another template. The <TT>lazy_enable_if</TT> 
and <TT>lazy_disable_if</TT> templates (and their <TT>_c</TT> versions) can be used in such
situations:
<PRE>template&lt;class T, class U&gt;
typename lazy_enable_if&lt;is_multipliable&lt;T, U&gt;, mult_traits&lt;T, U&gt; &gt;::type
operator*(const T&amp; t, const U&amp; u) { ... }

</PRE>The second argument of <TT>lazy_enable_if</TT> must be a class type
that defines a nested type named <TT>type</TT> whenever the first
parameter (the condition) is true.<BR>
<BR>
<!--TOC paragraph Note-->

<H5>Note</H5><!--SEC END -->

Referring to one member type or static constant in a traits class
causes all of the members (type and static constant) of that
specialization to be instantiated. Therefore, if your traits classes
can sometimes contain invalid types, you should use two distinct
templates for describing the conditions and the type mappings. In the
above example, <TT>is_multipliable&lt;T, U&gt;::value</TT> defines when
<TT>mult_traits&lt;T, U&gt;::type</TT> is valid.<BR>
<BR>
<!--TOC subsection Compiler workarounds-->

<H3><A NAME="htoc9">3.4</A>&nbsp;&nbsp;Compiler workarounds</H3><!--SEC END -->

<A NAME="sec:workarounds"></A>
Some compilers flag functions as ambiguous if the only distinguishing factor is a different 
condition in an enabler (even though the functions could never be ambiguous). For example,
some compilers (e.g. GCC 3.2) diagnose the following two functions as ambiguous:
<PRE>template &lt;class T&gt;
typename enable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
foo(T t);

template &lt;class T&gt;
typename disable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
foo(T t);

</PRE>Two workarounds can be applied:
<UL><LI>
Use an extra dummy parameter which disambiguates the functions. Use a default value for
it to hide the parameter from the caller. For example:
<PRE>template &lt;int&gt; struct dummy { dummy(int) {} };

template &lt;class T&gt;
typename enable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
foo(T t, dummy&lt;0&gt; = 0);

template &lt;class T&gt;
typename disable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
foo(T t, dummy&lt;1&gt; = 0);
</PRE><BR>
<BR>
<LI>Define the functions in different namespaces and bring them into a common
namespace with <TT>using</TT> declarations:
<PRE>namespace A {
  template &lt;class T&gt;
  typename enable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
  foo(T t);
}

namespace B {
  template &lt;class T&gt;
  typename disable_if&lt;boost::is_arithmetic&lt;T&gt;, T&gt;::type 
  foo(T t);
}

using A::foo;
using B::foo;

</PRE>
Note that the second workaround above cannot be used for member
templates. On the other hand, operators do not accept extra arguments,
which makes the first workaround unusable. As the net effect,
neither of the workarounds are of assistance for templated operators that
need to be defined as member functions (assignment and
subscript operators).
</UL>
<!--TOC section Acknowledgements-->

<H2><A NAME="htoc10">4</A>&nbsp;&nbsp;Acknowledgements</H2><!--SEC END -->

We are grateful to Howard Hinnant, Jason Shirk, Paul Mensonides, and Richard
Smith whose findings have influenced the library.<BR>
<BR>
<!--TOC section References-->

<H2>References</H2><!--SEC END -->
<DL COMPACT=compact><DT><A NAME="jarvi:03:cuj_arbitrary_overloading"><FONT COLOR=purple>[1]</FONT></A><DD>
Jaakko J&auml;rvi, Jeremiah Willcock, Howard Hinnant, and Andrew Lumsdaine.
Function overloading based on arbitrary properties of types.
<EM>C/C++ Users Journal</EM>, 21(6):25--32, June 2003.<BR>
<BR>
<DT><A NAME="jarvi:03:c++typeclasses"><FONT COLOR=purple>[2]</FONT></A><DD>
Jaakko J&auml;rvi, Jeremiah Willcock, and Andrew Lumsdaine.
Concept-controlled polymorphism.
In Frank Pfennig and Yannis Smaragdakis, editors, <EM>Generative
 Programming and Component Engineering</EM>, volume 2830 of <EM>LNCS</EM>, pages
 228--244. Springer Verlag, September 2003.<BR>
<BR>
<DT><A NAME="vandevoorde2002:templates"><FONT COLOR=purple>[3]</FONT></A><DD>
David Vandevoorde and Nicolai&nbsp;M. Josuttis.
<EM>C++ Templates: The Complete Guide</EM>.
Addison-Wesley, 2002.</DL>





<hr></hr>

<B>Contributed by:</B> <BR>
Jaakko J&auml;rvi, Jeremiah Willcock and Andrew Lumsdaine<BR>
<EM>{jajarvi|jewillco|lums}@osl.iu.edu</EM><BR>
Indiana University<BR>
Open Systems Lab
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